The Ford-Fulkerson algorithm is a method that resolves the max-flow min-cut problem. That is, given a network with vertices and edges between those vertices that have certain weights, how much “flow” can the network process at a time? Flow can mean anything, but typically it means data through a computer network. When the capacities are integers, the runtime of Ford–Fulkerson is bounded by O ( E *f ).
Ford-Fulkarson’s algorithm
Given a graph which represents a flow network where every edge has a capacity. Also given two vertices source ‘s’ and sink ‘t’ in the graph, find the maximum possible flow from s to t with following constraints:
- Flow on an edge doesn’t exceed the given capacity of the edge.
 - Incoming flow is equal to outgoing flow for every vertex except s and t.

 
The maximum possible flow in the above graph is 23.

Program in C :
#include <stdio.h>
#define WHITE 0
#define GRAY 1
#define BLACK 2
#define MAX_NODES 1000
#define oo 1000000000
int n;  // number of nodes
int e;  // number of edges
int capacity[MAX_NODES][MAX_NODES]; // capacity matrix
int flow[MAX_NODES][MAX_NODES];     // flow matrix
int color[MAX_NODES]; // needed for breadth-first search               
int pred[MAX_NODES];  // array to store augmenting path
int min (int x, int y) {
    return x<y ? x : y;  // returns minimum of x and y
}
int head,tail;
int q[MAX_NODES+2];
void enqueue (int x) {
    q[tail] = x;
    tail++;
    color[x] = GRAY;
}
int dequeue () {
    int x = q[head];
    head++;
    color[x] = BLACK;
    return x;
}
int bfs (int start, int target) {
    int u,v;
    for (u=0; u<n; u++) {
	color[u] = WHITE;
    }   
    head = tail = 0;
    enqueue(start);
    pred[start] = -1;
    while (head!=tail) {
	u = dequeue();
        // Search all adjacent white nodes v. If the capacity
        // from u to v in the residual network is positive,
        // enqueue v.
	for (v=0; v<n; v++) {
	    if (color[v]==WHITE && capacity[u][v]-flow[u][v]>0) {
		enqueue(v);
		pred[v] = u;
	    }
	}
    }
    // If the color of the target node is black now,
    // it means that we reached it.
    return color[target]==BLACK;
}
int max_flow (int source, int sink) {
    int i,j,u;
    // Initialize empty flow.
    int max_flow = 0;
    for (i=0; i<n; i++) {
	for (j=0; j<n; j++) {
	    flow[i][j] = 0;
	}
    }
    // While there exists an augmenting path,
    // increment the flow along this path.
    while (bfs(source,sink)) {
        // Determine the amount by which we can increment the flow.
	int increment = oo;
	for (u=n-1; pred[u]>=0; u=pred[u]) {
	    increment = min(increment,capacity[pred[u]][u]-flow[pred[u]][u]);
	}
        // Now increment the flow.
	for (u=n-1; pred[u]>=0; u=pred[u]) {
	    flow[pred[u]][u] += increment;
	    flow[u][pred[u]] -= increment;
	}
	max_flow += increment;
    }
    // No augmenting path anymore. We are done.
    return max_flow;
}
void read_input_file() {
    int a,b,c,i,j;
    FILE* input = fopen("data.txt","r");
    // read number of nodes and edges
    fscanf(input,"%d %d",&n,&e);
    printf("\nNumber of Vertices : %d   Edges : %d",n,e);
    // initialize empty capacity matrix 
    for (i=0; i<n; i++) {
	for (j=0; j<n; j++) {
	    capacity[i][j] = 0;
	}
    }
    // read edge capacities
    for (i=0; i<e; i++) {
	fscanf(input,"%d %d %d",&a,&b,&c);
	capacity[a][b] = c;
	printf("\nA : %d  B : %d  Capacity : %d",a,b,c);
    }
    fclose(input);
}
int main () {
    read_input_file();
    printf("\nPlease enter Source(s) and Sink(t) :\n");
    int s=0,t=n-1;
    scanf("%d %d",&s,&t);
    printf("\nMax Flow : %d\n",max_flow(s,t));
    return 0;
}Output:

Please comment below in case of any problem found during running the code or any other doubts.